I'm trying to convert integer to binary. This is my work. I don't know how the make a list to show the binary.
num_str = input("Please give me a integer: ") num_int = int(num_str) while num_int > 0: if num_int % 2 == 0: num_int = int(num_int / 2) num_remainder = 1 print("The remainder is:", 0) continue elif num_int % 2 == 1: num_int = int(num_int / 2) num_remainder = 1 print("The remainder is:", 1) continue How to make the remainder together?
18 Answers
Are you aware of the builtin bin function?
>>> bin(100) '0b1100100' >>> bin(1) '0b1' >>> bin(0) '0b0' You are on the right track, you just need to save the digits in a variable somewhere instead of just printing them to the screen:
num_str = input("Please give me a integer: ") num_int = int(num_str) num_bin_reversed = '' while num_int > 0: if num_int % 2 == 0: num_int = int(num_int / 2) num_remainder = 1 print("The remainder is:", 0) num_bin_reversed += '0' elif num_int % 2 == 1: num_int = int(num_int / 2) num_remainder = 1 print("The remainder is:", 1) num_bin_reversed += '1' num_bin = num_bin_reversed[::-1] if int(num_str) > 0: assert '0b' + num_bin == bin(int(num_str)) Now, try to fix it by making it work with negative numbers and 0 too!
1#First off yes there is an easier way to convert i.e bin(int) but where is the fun in that """First we ask the user to input a number. In Python 3+ raw input is gone so the variable integer_number will actually be a string""" integer_number = input('Please input an integer') #get integer whole number off user """We could use int(input('Please input an integer')) but we don't want to overload anyones brains so we show casting instead""" '''Next we convert the string to an integer value (cast). Unless the user enters text then the program will crash. You need to put your own error detection in''' integer_number = int(integer_number) """initialise a variable name result and assign it nothing. This so we can add to it later. You can't add things to a place that doesn't exist""" result = '' '''since we are creating an 8bit binary maximum possible number of 255 we set the for loop to 8 (dont forget that x starts at 0''' for x in range(8): #The variable in the for loop will increase by 1 each time #Next we get the modulos of the integer_number and assign it to the variable r r = integer_number % 2 #then we divide integer number by two and put the value back in integer_value #we use // instead of / for int division els it will be converted to a float point variable integer_number = integer_number//2 #Here we append the string value of r which is an integer to result result += str(r) #This then loops back to the for loop whilst x<8 #then we assign the reverse of result using [::-1] to result result = result[::-1] #print out the result print(result) You can store the remainders as digits in a string. Here is one possible function to convert from decimal to binary:
def dec2bin(d_num): assert d_num >= 0, "cannot convert negative number to binary" if d_num == 0: return '0' b_num = "" while d_num > 0: b_num = str(d_num%2) + b_num d_num = d_num//2 return b_num #This is the same code as the one above it's just without comments #This program takes a number from the user and turns it into an 8bit binary string integer_number = int(input('Please input an integer')) result = '' for x in range(8): r = integer_number % 2 integer_number = integer_number//2 result += str(r) result = result[::-1] print(result) here is a code that works in python 3.3.0 the converts binary to integer and integer to binary, JUST COPY AND PASTE!!!
def B2D(): decnum = int(input("Please enter a binary number"), 2) print(decnum) welcome() def D2B(): integer_number = input('Please input an integer') integer_number = int(integer_number) result = '' for x in range(8): r = integer_number % 2 integer_number = integer_number//2 result += str(r) result = result[::-1] print(result) welcome() def welcome(): print("*********************************************************") print ("Welcome to the binary converter program") print ("What would you like to do?") print ("Type 1 to convert from denary to binary") print ("Type 2 to convert from binary to denary") print ("Type 3 to exit out of this program") choice = input("") if choice == '1': D2B() elif choice == '2': B2D() elif choice == '3': print("Goodbye") exit welcome() I give thanks to nikpod. His code helped me give out my own answer. Hope this helps.
# Define your functions here. def int_to_reverse_binary(num): string = '' while num > 0: string += str(num % 2) num = num // 2 return string def string_reverse(string_to_reverse): return string_to_reverse[::-1] if __name__ == '__main__': # Type your code here. # Your code must call int_to_reverse_binary() to get # the binary string of an integer in a reverse order. # Then call string_reverse() to reverse the string # returned from int_to_reverse_binary(). num = int(input()) binary = int_to_reverse_binary(num) print(string_reverse(binary)) Sheesh some of these examples are very complicated for a Python noob like me.
This is the way I did the lab(Please let me know what you think):
First, the way the lab wants to see it is in reverse(not correct binary but that's the way the lab wants to see it):
x = int(input()) bin_number = '' while x > 0: result = x % 2 bin_number = str(bin_number) + str(result) x = x // 2 if x < 1: break continue print(bin_number) Second, prints the result in the correct order(but incorrect for the lab)
x = int(input()) bin_number = '' while x > 0: result = x % 2 bin_number = str(bin_number) + str(result) rev_bin_number = bin_number[::-1] x = x // 2 if x < 1: break continue print(rev_bin_number) ncG1vNJzZmirpJawrLvVnqmfpJ%2Bse6S7zGiorp2jqbawutJoaG1taWuAd4OOrqqippdivbrAx6ilZqyfYrCwutWeqa1lmaPBprPEq2Stp12Xtq%2Bt0bI%3D